![]() Substituting the values in the above formula we get, Hence by the formula for calculating range: R= d = V₀² * sin(2 * α) / g The Horizontal Range is the horizontal distance given by x at t = t2. The angle of the projection of the object is 40 degrees The velocity of an object in ‘y’ direction as 40m/s Calculate the range that is covered by the object? Take the time of flight as 6.25 sec to make the calculations easier. Question 1: An object in the influence of an external force is launched at a velocity of 40 m/s in a direction making an angle of 40° upward with the horizontal. The range of the projectile also depends on the angle at which the object is thrown.įor more concepts check out to get quick answers by using this free tool. Like the time of flight and maximum height, the range of the projectile is a function and is linearly dependent on the initial speed of the object under the influence of the external force. This line is represented as a straight horizontal line in the diagrams. There is no acceleration in this direction of the motion since gravity only acts vertically on the object. The range of the projectile is defined as the displacement in the horizontal direction of the motion of the object. So 45 degrees is the only or the best angle at which the maximum height of the projectile can be achieved for any object or projectile following a trajectory under projectile motion. We can solve this quite easily by differentiating the formula and equating it with zero hence getting the answer as 45 degrees. With the help of formulas, one can calculate at which angle an object or projectile be thrown so that it gains maximum height. The net of both cos and sin is taken as the final angle in the calculations.
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